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Extra info for Air Conditioning Clinic Cooling and Heating Load Estimation One of the Fundamental Series TRG-TRC002-EN

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For the example used in this clinic, we will assume that fan heat gains and other system heat gains are negligible. FRQGXFWLRQ WKURXJK URRI FRQGXFWLRQ WKURXJK H[WHULRU ZDOO FRQGXFWLRQ WKURXJK ZLQGRZV VRODU UDGLDWLRQ WKURXJK ZLQGRZV SHRSOH OLJKWV HTXLSPHQW LQILOWUDWLRQ WRWDO VSDFH FRROLQJ ORDG YHQWLODWLRQ WRWDO FRLO FRROLQJ ORDG VHQVLEOH ORDG %WXKU >:@  >@  >@  >@  >@  >@  >@  >@  >@  >@  >@  >@ ODWHQW ORDG %WXKU >:@  >@  >@  >@  >@  >@  >@ Figure 54 In summary, the total cooling load for our example space is made up of the following components: n Conduction heat gain from outdoors through the roof and west-facing exterior wall and windows n Solar radiation heat gain through the west-facing windows n Internal heat gains from people, lights, office equipment, and a coffee maker in the space n Heat gain due to hot, humid air infiltrating into the space from outdoors In addition, the cooling coil in the building HVAC system has to cool the outdoor air that is deliberately brought into the building for ventilation purposes.

There are three methods commonly used to estimate infiltration airflow. 38 TRG-TRC002-EN period two Cooling Load Estimation notes The air change method is the easiest, but may be the least accurate of these methods. It involves estimating the number of air changes per hour that can be expected in spaces of a certain construction quality. Using this method, the quantity of infiltration air is estimated using the equation: infiltration airflow = (volume of space × air change rate) ÷ 60 [infiltration airflow = (volume of space × air change rate) ÷ 3,600] where, n Infiltration airflow = quantity of air infiltrating into the space, cfm [m3/s] n Volume of space = length × width × height of space, ft3 [m3] n Air change rate = air changes per hour n 60 = conversion from hours to minutes n 3,600 = conversion from hours to seconds The crack method is a little more complex and is based upon the average quantity of air known to enter through cracks around windows and doors when the wind velocity is constant.

For the example used in this clinic, we will assume that fan heat gains and other system heat gains are negligible. FRQGXFWLRQ WKURXJK URRI FRQGXFWLRQ WKURXJK H[WHULRU ZDOO FRQGXFWLRQ WKURXJK ZLQGRZV VRODU UDGLDWLRQ WKURXJK ZLQGRZV SHRSOH OLJKWV HTXLSPHQW LQILOWUDWLRQ WRWDO VSDFH FRROLQJ ORDG YHQWLODWLRQ WRWDO FRLO FRROLQJ ORDG VHQVLEOH ORDG %WXKU >:@  >@  >@  >@  >@  >@  >@  >@  >@  >@  >@  >@ ODWHQW ORDG %WXKU >:@  >@  >@  >@  >@  >@  >@ Figure 54 In summary, the total cooling load for our example space is made up of the following components: n Conduction heat gain from outdoors through the roof and west-facing exterior wall and windows n Solar radiation heat gain through the west-facing windows n Internal heat gains from people, lights, office equipment, and a coffee maker in the space n Heat gain due to hot, humid air infiltrating into the space from outdoors In addition, the cooling coil in the building HVAC system has to cool the outdoor air that is deliberately brought into the building for ventilation purposes.

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Air Conditioning Clinic Cooling and Heating Load Estimation One of the Fundamental Series TRG-TRC002-EN by The Trane Company


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